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Popular >

extreme f(x)= 4/3 x^2-4x

Solution

extreme points

f (x) = \frac{4}{3} x^{2} - 4 x

Solution

Minimum (\frac{3}{2}, - 3)

Solution steps

f^{'} (x) = \frac{8 x}{3} - 4

Find intervals:

Decreasing

: - \infty < x < \frac{3}{2},

Increasing

: \frac{3}{2} < x < \infty

Plug

x = \frac{3}{2}

into

\frac{4}{3} x^{2} - 4 x : - 3

Minimum (\frac{3}{2}, - 3)

Popular Examples

extreme f(x)=-0.04x^2+42x-500 extreme points

f (x) = - 0.04 x^{2} + 42 x - 500

extreme f(x)=x^5-10x^4+2=x^4(x-10)+2 extreme points

f (x) = x^{5} - 10 x^{4} + 2 = x^{4} (x - 10) + 2

extreme f(x)=x^9-x^7 extreme points

f (x) = x^{9} - x^{7}

extreme f(x,y)=x^2+2y^2-4x+4y+6 extreme points

f (x, y) = x^{2} + 2 y^{2} - 4 x + 4 y + 6

extreme f(x)=ln(4x)-8x^2 extreme points

f (x) = ln (4 x) - 8 x^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 4/3 x^2-4x ?
The extreme f(x)= 4/3 x^2-4x is Minimum(3/2 ,-3)