What is the extreme f(x,y)=40x^{3/4}y^{1/4} ?

The extreme f(x,y)=40x^{3/4}y^{1/4} is None

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extreme f(x,y)=40x^{3/4}y^{1/4}

extreme points

f (x, y) = 40 x^{\frac{3}{4}} y^{\frac{1}{4}}

None

Solution steps

Find the critical points:

None

40 x^{\frac{3}{4}} y^{\frac{1}{4}}

has no critical points, therefore there are no extreme points

None

y = 9 e^{- 2 t} - 7 e^{- 3 t}

18 x - 8

x^{6} - x^{4} + 4 x^{3} - 2 x

f (x) = (x^{2} - 4)^{4} (x^{2} + 1)^{5}

\frac{2 x - ln ( 3 x )}{x}

What is the extreme f(x,y)=40x^{3/4}y^{1/4} ?
The extreme f(x,y)=40x^{3/4}y^{1/4} is None