What is the extreme f(x)=2x^3+21x^2+72x-2 ?

The extreme f(x)=2x^3+21x^2+72x-2 is Maximum(-4,-82),Minimum(-3,-83)

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extreme f(x)=2x^3+21x^2+72x-2

extreme points

f (x) = 2 x^{3} + 21 x^{2} + 72 x - 2

Maximum (- 4, - 82), Minimum (- 3, - 83)

Solution steps

f^{'} (x) = 6 x^{2} + 42 x + 72

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < - 3,

Increasing

: - 3 < x < \infty

Plug

x = - 4

into

2 x^{3} + 21 x^{2} + 72 x - 2 : - 82

Maximum (- 4, - 82)

Plug

x = - 3

into

2 x^{3} + 21 x^{2} + 72 x - 2 : - 83

Minimum (- 3, - 83)

Maximum (- 4, - 82), Minimum (- 3, - 83)

f (x) = 4 cos (3 x)

ln (e^{\frac{u + v}{2}}) - v

f (x) = 6 x^{2} - 6 x - 72

f (x) = 4 x^{5} - 3 x^{4} + x^{3} - 2 x^{2} + x - 1

f (x, y) = 5 x^{2} + 3 x y + 2 y^{2}

What is the extreme f(x)=2x^3+21x^2+72x-2 ?
The extreme f(x)=2x^3+21x^2+72x-2 is Maximum(-4,-82),Minimum(-3,-83)