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Popular >

extreme y=x^2-8x

Solution

extreme points

y = x^{2} - 8 x

Solution

Minimum (4, - 16)

Solution steps

f^{'} (x) = 2 x - 8

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} - 8 x : - 16

Minimum (4, - 16)

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Frequently Asked Questions (FAQ)

What is the extreme y=x^2-8x ?
The extreme y=x^2-8x is Minimum(4,-16)