What is the extreme f(x)=((e^x))/(1+x^2) ?

The extreme f(x)=((e^x))/(1+x^2) is Saddle(1, e/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=((e^x))/(1+x^2)

extreme points

f (x) = \frac{( e ^{x} )}{1 + x ^{2}}

Saddle (1, \frac{e}{2})

Solution steps

f^{'} (x) = \frac{e ^{x} ( 1 + x ^{2} ) - 2 x e ^{x}}{( 1 + x ^{2} ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

\frac{e ^{x}}{1 + x ^{2}} : \frac{e}{2}

Saddle (1, \frac{e}{2})

f (x) = 2 (4 x)^{x}

f (x, y) = 2 x^{3} - 6 x y + 3 y^{2}

y = sin (x) cos (x)

f (x, y) = x^{3} + y^{3} + 7 x y

f (x) = 59.80 8^{2} - 11.148 x

What is the extreme f(x)=((e^x))/(1+x^2) ?
The extreme f(x)=((e^x))/(1+x^2) is Saddle(1, e/2)