What is the extreme g(x)=x^3-9x ?

The extreme g(x)=x^3-9x is Maximum(-sqrt(3),6sqrt(3)),Minimum(sqrt(3),-6sqrt(3))

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extreme g(x)=x^3-9x

extreme points

g (x) = x^{3} - 9 x

Maximum (- 3, 63), Minimum (3, - 63)

Solution steps

f^{'} (x) = 3 x^{2} - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{3} - 9 x : 63

Maximum (- 3, 63)

Plug

x = 3

into

x^{3} - 9 x : - 63

Minimum (3, - 63)

Maximum (- 3, 63), Minimum (3, - 63)

(x^{2} - 1)^{3}, - 1 \leq x \leq 6

x \cdot e^{- 2 x^{2}}

f (x) = x^{4} + 4 x^{3} + 10

P (a, b) = 3 + 2 a^{2} b + 4 a b^{2} + 8 b^{3}

What is the extreme g(x)=x^3-9x ?
The extreme g(x)=x^3-9x is Maximum(-sqrt(3),6sqrt(3)),Minimum(sqrt(3),-6sqrt(3))