extreme f(x)=6x^2-8x+2

الحلّ

extreme points

f (x) = 6 x^{2} - 8 x + 2

صغرى (\frac{2}{3}, - \frac{2}{3})

خطوات الحلّ

f^{'} (x) = 12 x - 8

Find intervals:

تنازليّة

: - \infty < x < \frac{2}{3},

تصاعديّة

: \frac{2}{3} < x < \infty

Plug

x = \frac{2}{3}

into

6 x^{2} - 8 x + 2 : - \frac{2}{3}

صغرى (\frac{2}{3}, - \frac{2}{3})

f (x) = ∣ 2 x + 1 ∣

\frac{1}{∣ x ∣ + 1}

f (x, y) = e^{2 x} (x + y^{2} + 2 y) + 10

P (x, y) = x^{2} - y^{2}

f (x) = x \cdot ln^{2} (x)