What is the extreme f(x)=355x^2-1420x^3 ?

The extreme f(x)=355x^2-1420x^3 is Minimum(0,0),Maximum(1/6 , 355/108)

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extreme f(x)=355x^2-1420x^3

extreme points

f (x) = 355 x^{2} - 1420 x^{3}

Minimum (0, 0), Maximum (\frac{1}{6}, \frac{355}{108})

Solution steps

f^{'} (x) = 710 x - 4260 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \frac{1}{6},

Decreasing

: \frac{1}{6} < x < \infty

Plug

x = 0

into

355 x^{2} - 1420 x^{3} : 0

Minimum (0, 0)

Plug

x = \frac{1}{6}

into

355 x^{2} - 1420 x^{3} : \frac{355}{108}

Maximum (\frac{1}{6}, \frac{355}{108})

Minimum (0, 0), Maximum (\frac{1}{6}, \frac{355}{108})

6 + 9 x^{2} - 6 x^{3}

f (x) = 5 x^{4} - x^{5} + 5

f (x) = 2 x + 4 sin (x)

f (x) = x^{2} - 6 x - 8

f (x) = 6 x^{2} - 6

What is the extreme f(x)=355x^2-1420x^3 ?
The extreme f(x)=355x^2-1420x^3 is Minimum(0,0),Maximum(1/6 , 355/108)