What is the extreme f(x)=6x^2-10y^2 ?

The extreme f(x)=6x^2-10y^2 is Saddle(0,0)

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extreme f(x)=6x^2-10y^2

extreme points

f (x) = 6 x^{2} - 10 y^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 20

D (x, y) = - 240

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = x^{4} - 4 x - 6

f (x, y) = x^{3} + y^{3} - 12 x - 15 y

f (x) = \frac{x + 6}{x - 3}

y = 4 x - 9 x^{\frac{4}{9}}

f (x) = 2 x^{3} + 3 x^{2} - 72 x + 1, - 4 \leq x \leq 7

What is the extreme f(x)=6x^2-10y^2 ?
The extreme f(x)=6x^2-10y^2 is Saddle(0,0)