What is the extreme T(x,y)=26-9x^2-9y^2 ?

The extreme T(x,y)=26-9x^2-9y^2 is Maximum(0,0)

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extreme T(x,y)=26-9x^2-9y^2

extreme points

T (x, y) = 26 - 9 x^{2} - 9 y^{2}

Maximum (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 18

D (x, y) = 324

Check the sign of at each critical point

Check critical point

(0, 0) :

Maximum

Maximum (0, 0)

y = 6 x^{2} - 30 x + 9

f (x) = - 15 - 7 x - x^{2}

f (x, y) = - x^{2} + 1 - - y^{2} + 1

F (x, y) = 3 x^{2} y - 2 x y^{2} + x + C

f (x) = (2 x)^{x}

What is the extreme T(x,y)=26-9x^2-9y^2 ?
The extreme T(x,y)=26-9x^2-9y^2 is Maximum(0,0)