What is the extreme f(x,y)=2x^2-5y^2+6y ?

The extreme f(x,y)=2x^2-5y^2+6y is Saddle(0, 3/5)

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extreme f(x,y)=2x^2-5y^2+6y

extreme points

f (x, y) = 2 x^{2} - 5 y^{2} + 6 y

Saddle (0, \frac{3}{5})

Solution steps

Find the critical points:

(0, \frac{3}{5})

\frac{\partial ^{2} f}{\partial x ^{2}} = - 10

D (x, y) = - 40

Check the sign of at each critical point

Check critical point

(0, \frac{3}{5}) :

Saddle

Saddle (0, \frac{3}{5})

f (x, y) = (x + y)

f (x) = y^{3} - 3 x y + x^{3}

cos (4 x)

f (x) = (x - 4)^{3}

- 2 x^{2} + 324 ln (x)

What is the extreme f(x,y)=2x^2-5y^2+6y ?
The extreme f(x,y)=2x^2-5y^2+6y is Saddle(0, 3/5)