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Popular >

extreme f(x)=-7/(x^2+1)

Solution

extreme points

f (x) = - \frac{7}{x ^{2} + 1}

Solution

Minimum (0, - 7)

Solution steps

f^{'} (x) = \frac{14 x}{( x ^{2} + 1 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

- \frac{7}{x ^{2} + 1} : - 7

Minimum (0, - 7)

Graph

Popular Examples

extreme f(x)= x/(25-x+x^2)extreme points

f (x) = \frac{x}{25 - x + x ^{2}}

extreme f(x)=(x^2-25)^2 extreme points

f (x) = (x^{2} - 25)^{2}

extreme f(x,y)=x^2+2y^2-x+3 extreme points

f (x, y) = x^{2} + 2 y^{2} - x + 3

extreme (x^2+12)(144-x^2)extreme points

(x^{2} + 12) (144 - x^{2})

extreme f(x)=(10x^3)/3-(11x^2)/2+x+2 extreme points

f (x) = \frac{10 x ^{3}}{3} - \frac{11 x ^{2}}{2} + x + 2

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-7/(x^2+1) ?
The extreme f(x)=-7/(x^2+1) is Minimum(0,-7)