What is the extreme f(x)=x^7ln(x) ?

The extreme f(x)=x^7ln(x) is Minimum(1/(\sqrt[7]{e)},-1/(7e))

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extreme f(x)=x^7ln(x)

extreme points

f (x) = x^{7} ln (x)

Solution steps

f^{'} (x) = 7 x^{6} ln (x) + x^{6}

Find intervals:

Decreasing

Increasing

Plug

into

x^{7} ln (x) : - \frac{1}{7 e}

f (x) = \frac{1}{3} x^{3} + \frac{11}{2} x^{2} + 24 x + 1

f (x) = x^{4} (x + 2)^{2}

f (y, x) = \frac{500}{4 + x ^{2} + y ^{2}}

f (x) = \frac{x + 3}{x ^{2} - 4 x - 21}

What is the extreme f(x)=x^7ln(x) ?
The extreme f(x)=x^7ln(x) is Minimum(1/(\sqrt[7]{e)},-1/(7e))