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Popular >

extreme f(x)=x^{(2/3)}

Solution

extreme points

f (x) = x^{(\frac{2}{3})}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{2}{3 x ^{\frac{1}{3}}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{\frac{2}{3}} : 0

Minimum (0, 0)

Popular Examples

extreme f(x)=((x+4))/(x^2-3x-28)extreme points

f (x) = \frac{( x + 4 )}{x ^{2} - 3 x - 28}

extreme f(x,y)=3x+5y+2 extreme points

f (x, y) = 3 x + 5 y + 2

extreme f(x)=(2x^2-x-2)/(x+1)extreme points

f (x) = \frac{2 x ^{2} - x - 2}{x + 1}

extreme f(x)=x^3-6x^2+9x,0<= x<= 2 extreme points

f (x) = x^{3} - 6 x^{2} + 9 x, 0 \leq x \leq 2

extreme f(x)=(x-2)(x+1)^3 extreme points

f (x) = (x - 2) (x + 1)^{3}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^{(2/3)} ?
The extreme f(x)=x^{(2/3)} is Minimum(0,0)