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Popular >

extreme f(x)=12x^2-48x+20

Solution

extreme points

f (x) = 12 x^{2} - 48 x + 20

Solution

Minimum (2, - 28)

Solution steps

f^{'} (x) = 24 x - 48

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

12 x^{2} - 48 x + 20 : - 28

Minimum (2, - 28)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=12x^2-48x+20 ?
The extreme f(x)=12x^2-48x+20 is Minimum(2,-28)