What is the extreme f(x)=0.5x^2+15x+5000 ?

The extreme f(x)=0.5x^2+15x+5000 is Minimum(-15,4887.5)

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extreme f(x)=0.5x^2+15x+5000

extreme points

f (x) = 0.5 x^{2} + 15 x + 5000

Minimum (- 15, 4887.5)

Solution steps

f^{'} (x) = x + 15

Find intervals:

Decreasing

: - \infty < x < - 15,

Increasing

: - 15 < x < \infty

Plug

x = - 15

into

0.5 x^{2} + 15 x + 5000 : 4887.5

Minimum (- 15, 4887.5)

f (x) = \frac{x ^{5}}{20} - 1 x^{3}

\frac{x ^{2} + 4 x}{x ^{3} - 17 x ^{2} + 72 x}

f (x) = 3 x^{3} - 3 x^{2} - 3 x + 10

0.5 x + 15 + \frac{5000}{x}

f (x) = 5 x^{3} - 6

What is the extreme f(x)=0.5x^2+15x+5000 ?
The extreme f(x)=0.5x^2+15x+5000 is Minimum(-15,4887.5)