en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-4x^2+48x-108

Solution

extreme points

f (x) = - 4 x^{2} + 48 x - 108

Solution

Maximum (6, 36)

Solution steps

f^{'} (x) = - 8 x + 48

Find intervals:

Increasing

: - \infty < x < 6,

Decreasing

: 6 < x < \infty

Plug

x = 6

into

- 4 x^{2} + 48 x - 108 : 36

Maximum (6, 36)

Graph

Popular Examples

extreme f(x)=3x-5x^2,(-infinity <x<= 2)extreme points

f (x) = 3 x - 5 x^{2}, (- \infty < x \leq 2)

extreme f(x)=5(10-x)+3(sqrt(16+x^2))extreme points

f (x) = 5 (10 - x) + 3 (16 + x^{2})

extreme 13x^2-x^3 extreme points

13 x^{2} - x^{3}

extreme f(x)=2+12x-x^2 extreme points

f (x) = 2 + 12 x - x^{2}

extreme f(x)=(x-3)(x+1)(x+4)extreme points

f (x) = (x - 3) (x + 1) (x + 4)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-4x^2+48x-108 ?
The extreme f(x)=-4x^2+48x-108 is Maximum(6,36)