What is the extreme f(x)=2x^3-15x^2+6 ?

The extreme f(x)=2x^3-15x^2+6 is Maximum(0,6),Minimum(5,-119)

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extreme f(x)=2x^3-15x^2+6

extreme points

f (x) = 2 x^{3} - 15 x^{2} + 6

Maximum (0, 6), Minimum (5, - 119)

Solution steps

f^{'} (x) = 6 x^{2} - 30 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 0

into

2 x^{3} - 15 x^{2} + 6 : 6

Maximum (0, 6)

Plug

x = 5

into

2 x^{3} - 15 x^{2} + 6 : - 119

Minimum (5, - 119)

Maximum (0, 6), Minimum (5, - 119)

(x - 7) e^{x}

y = 3 - 5 (x + 1)^{2}

f (x) = 5 x^{5} - 2 x + 1

\frac{x ^{2}}{x ^{2} + 192}

f (x y) = ln (x + y - 1)

What is the extreme f(x)=2x^3-15x^2+6 ?
The extreme f(x)=2x^3-15x^2+6 is Maximum(0,6),Minimum(5,-119)