What is the extreme f(x)=2x^3-2x^2-2x+4 ?

The extreme f(x)=2x^3-2x^2-2x+4 is Maximum(-1/3 , 118/27),Minimum(1,2)

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extreme f(x)=2x^3-2x^2-2x+4

extreme points

f (x) = 2 x^{3} - 2 x^{2} - 2 x + 4

Maximum (- \frac{1}{3}, \frac{118}{27}), Minimum (1, 2)

Solution steps

f^{'} (x) = 6 x^{2} - 4 x - 2

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

2 x^{3} - 2 x^{2} - 2 x + 4 : \frac{118}{27}

Maximum (- \frac{1}{3}, \frac{118}{27})

Plug

x = 1

into

2 x^{3} - 2 x^{2} - 2 x + 4 : 2

Minimum (1, 2)

Maximum (- \frac{1}{3}, \frac{118}{27}), Minimum (1, 2)

f (x) = 2 x^{3} - 2 x^{2} - 2 x + 9

f (x) = - 5 x^{3} + x^{2} + x - 7

f (x) = x^{\frac{4}{7}} (3 x + 11)

f (x) = - 0.2 x^{2} + 1.6 x + 98.6

6 x + 18

What is the extreme f(x)=2x^3-2x^2-2x+4 ?
The extreme f(x)=2x^3-2x^2-2x+4 is Maximum(-1/3 , 118/27),Minimum(1,2)