What is the extreme f(x)=2x+(20)/x ?

The extreme f(x)=2x+(20)/x is Maximum(-sqrt(10),-4sqrt(10)),Minimum(sqrt(10),4sqrt(10))

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extreme f(x)=2x+(20)/x

extreme points

f (x) = 2 x + \frac{20}{x}

Maximum (- 10, - 410), Minimum (10, 410)

Solution steps

f^{'} (x) = 2 - \frac{20}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 10,

Decreasing

: - 10 < x < 0,

Decreasing

: 0 < x < 10,

Increasing

: 10 < x < \infty

Plug

x = - 10

into

2 x + \frac{20}{x} : - 410

Maximum (- 10, - 410)

Plug

x = 10

into

2 x + \frac{20}{x} : 410

Minimum (10, 410)

Maximum (- 10, - 410), Minimum (10, 410)

12 x - 4 x^{2}

f (x, y) = x^{3} + y^{2} - 6 x y - 29 x + 18 y + 20

f (x) = 4 + 81 x - 3 x^{3}, 0 \leq x \leq 4

f (x) = x^{2} - 6 x + 13

y = 2 x^{3} - 12 x^{2} + 9

What is the extreme f(x)=2x+(20)/x ?
The extreme f(x)=2x+(20)/x is Maximum(-sqrt(10),-4sqrt(10)),Minimum(sqrt(10),4sqrt(10))