What is the extreme f(x)=-7x^3+21x+5 ?

The extreme f(x)=-7x^3+21x+5 is Minimum(-1,-9),Maximum(1,19)

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extreme f(x)=-7x^3+21x+5

extreme points

f (x) = - 7 x^{3} + 21 x + 5

Minimum (- 1, - 9), Maximum (1, 19)

Solution steps

f^{'} (x) = - 21 x^{2} + 21

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- 7 x^{3} + 21 x + 5 : - 9

Minimum (- 1, - 9)

Plug

x = 1

into

- 7 x^{3} + 21 x + 5 : 19

Maximum (1, 19)

Minimum (- 1, - 9), Maximum (1, 19)

f (x) = 0.001 x^{2} + 2.4 x - 90

f (x, y) = 8 x^{3} - 5 x^{2} y + 3 x y^{2}

g (x) = 6 x^{4} - 32 x^{3} + 48 x^{2} - 7

f (x) = tan (\frac{π x}{20}), 0 \leq x \leq 5

f (x, y) = - x^{2} y + x y^{2}

What is the extreme f(x)=-7x^3+21x+5 ?
The extreme f(x)=-7x^3+21x+5 is Minimum(-1,-9),Maximum(1,19)