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Popular >

extreme f(x)=-x^2+8ln(x)

Solution

extreme points

f (x) = - x^{2} + 8 ln (x)

Solution

Maximum (2, - 4 + 8 ln (2))

Solution steps

f^{'} (x) = - 2 x + \frac{8}{x}

Find intervals:

Increasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 2

into

- x^{2} + 8 ln (x) : - 4 + 8 ln (2)

Maximum (2, - 4 + 8 ln (2))

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=-x^2+8ln(x) ?
The extreme f(x)=-x^2+8ln(x) is Maximum(2,-4+8ln(2))