What is the extreme f(x)=-0.3x^2+2.4x+98.8 ?

The extreme f(x)=-0.3x^2+2.4x+98.8 is Maximum(4,103.6)

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extreme f(x)=-0.3x^2+2.4x+98.8

extreme points

f (x) = - 0.3 x^{2} + 2.4 x + 98.8

Maximum (4, 103.6)

Solution steps

f^{'} (x) = - 0.6 x + 2.4

Find intervals:

Increasing

: - \infty < x < 4,

Decreasing

: 4 < x < \infty

Plug

x = 4

into

- 0.3 x^{2} + 2.4 x + 98.8 : 103.6

Maximum (4, 103.6)

\frac{2}{x + 3} - 1

f (x, y) = x y + e^{x y}

f (x, y) = x^{3} + 3 \cdot x \cdot y - y^{2}

f (x) = 4 ln (2 x e^{- x})

f (x) = 2 x^{3} - 3 x + 6

What is the extreme f(x)=-0.3x^2+2.4x+98.8 ?
The extreme f(x)=-0.3x^2+2.4x+98.8 is Maximum(4,103.6)