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Popular >

extreme f(x)=x^2-8x+40

Solution

extreme points

f (x) = x^{2} - 8 x + 40

Solution

Minimum (4, 24)

Solution steps

f^{'} (x) = 2 x - 8

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} - 8 x + 40 : 24

Minimum (4, 24)

Graph

Popular Examples

extreme f(x)=x^2-8x+18 extreme points

f (x) = x^{2} - 8 x + 18

extreme f(x)= x/(x^2+4),-5<= x<= 5 extreme points

f (x) = \frac{x}{x ^{2} + 4}, - 5 \leq x \leq 5

extreme f(x)=-x^2-x-1 extreme points

f (x) = - x^{2} - x - 1

extreme f(x)=5(x-3)^2+2 extreme points

f (x) = 5 (x - 3)^{2} + 2

extreme (e^x)/(4+e^x)extreme points

\frac{e ^{x}}{4 + e ^{x}}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-8x+40 ?
The extreme f(x)=x^2-8x+40 is Minimum(4,24)