What is the extreme f(x)=x^3-3x^2-9x-3 ?

The extreme f(x)=x^3-3x^2-9x-3 is Maximum(-1,2),Minimum(3,-30)

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extreme f(x)=x^3-3x^2-9x-3

extreme points

f (x) = x^{3} - 3 x^{2} - 9 x - 3

Maximum (- 1, 2), Minimum (3, - 30)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x - 3 : 2

Maximum (- 1, 2)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x - 3 : - 30

Minimum (3, - 30)

Maximum (- 1, 2), Minimum (3, - 30)

f (x) = x^{3} - 8 x^{2} - 12 x + 1

f (x) = 3 cos (x), 0 \leq x \leq 4 π

4 x + 6 y - x^{2} - y^{2}

f (x) = x^{2} 3 - x

f (x) = 1 - x

What is the extreme f(x)=x^3-3x^2-9x-3 ?
The extreme f(x)=x^3-3x^2-9x-3 is Maximum(-1,2),Minimum(3,-30)