What is the extreme f(x)=-(10)/(x^2-3x+14) ?

The extreme f(x)=-(10)/(x^2-3x+14) is Minimum(3/2 ,-40/47)

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extreme f(x)=-(10)/(x^2-3x+14)

extreme points

f (x) = - \frac{10}{x ^{2} - 3 x + 14}

Minimum (\frac{3}{2}, - \frac{40}{47})

Solution steps

f^{'} (x) = \frac{10 ( 2 x - 3 )}{( x ^{2} - 3 x + 14 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < \frac{3}{2},

Increasing

: \frac{3}{2} < x < \infty

Plug

x = \frac{3}{2}

into

- \frac{10}{x ^{2} - 3 x + 14} : - \frac{40}{47}

Minimum (\frac{3}{2}, - \frac{40}{47})

y = x^{2} + 3

f (x, y) = \frac{1}{3 ^{- x^{2} - y^{2}} + 1}

f (x) = - sin^{2} (x), - π \leq x \leq π

\frac{- 6}{x - 7}

f (x) = x (22 - 40 + 2 x) (\frac{40}{2} - x)

What is the extreme f(x)=-(10)/(x^2-3x+14) ?
The extreme f(x)=-(10)/(x^2-3x+14) is Minimum(3/2 ,-40/47)