What is the extreme f(x)=2x^3+3x^2-120x+7 ?

The extreme f(x)=2x^3+3x^2-120x+7 is Maximum(-5,432),Minimum(4,-297)

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extreme f(x)=2x^3+3x^2-120x+7

extreme points

f (x) = 2 x^{3} + 3 x^{2} - 120 x + 7

Maximum (- 5, 432), Minimum (4, - 297)

Solution steps

f^{'} (x) = 6 x^{2} + 6 x - 120

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 5

into

2 x^{3} + 3 x^{2} - 120 x + 7 : 432

Maximum (- 5, 432)

Plug

x = 4

into

2 x^{3} + 3 x^{2} - 120 x + 7 : - 297

Minimum (4, - 297)

Maximum (- 5, 432), Minimum (4, - 297)

f (x) = 2 x^{3} + 3 x^{2} - 120 x + 1

f (x) = (\frac{4860}{x}) + 17 x + 752.774

f (x, y) = 2 y^{3} - 6 x y - x^{2}

f (x) = x \cdot \frac{( 1 - x ) ^{2}}{( 1 + x ) ^{2}}

\frac{4 + x}{9 - x}, - 9 \leq x \leq 0

What is the extreme f(x)=2x^3+3x^2-120x+7 ?
The extreme f(x)=2x^3+3x^2-120x+7 is Maximum(-5,432),Minimum(4,-297)