What is the extreme f(x)=(x^2+10x+16)/(x^2+4x+4) ?

The extreme f(x)=(x^2+10x+16)/(x^2+4x+4) is None

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extreme f(x)=(x^2+10x+16)/(x^2+4x+4)

extreme points

f (x) = \frac{x ^{2} + 10 x + 16}{x ^{2} + 4 x + 4}

None

Solution steps

f^{'} (x) = - \frac{6}{( x + 2 ) ^{2}}

Find intervals:

None

None

\frac{2 ln ( x + 4 )}{x + 4}

2 x - x^{2}

f (x) = x^{4} - 3 x^{3} - 12 x^{2}

f (x) = 17 + 7 x + x^{2}

f (x) = 2 (x^{2} - 6 x + 18)

What is the extreme f(x)=(x^2+10x+16)/(x^2+4x+4) ?
The extreme f(x)=(x^2+10x+16)/(x^2+4x+4) is None