What is the extreme f(x)=x^3+12x^2-27x+8[-10] ?

The extreme f(x)=x^3+12x^2-27x+8[-10] is Maximum(-9,406),Minimum(1,-94)

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extreme f(x)=x^3+12x^2-27x+8[-10]

extreme points

f (x) = x^{3} + 12 x^{2} - 27 x + 8 [- 10]

Maximum (- 9, 406), Minimum (1, - 94)

Solution steps

f^{'} (x) = 3 x^{2} + 24 x - 27

Find intervals:

Increasing

: - \infty < x < - 9,

Decreasing

: - 9 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 9

into

x^{3} + 12 x^{2} - 27 x + 8 [- 10] : 406

Maximum (- 9, 406)

Plug

x = 1

into

x^{3} + 12 x^{2} - 27 x + 8 [- 10] : - 94

Minimum (1, - 94)

Maximum (- 9, 406), Minimum (1, - 94)

f (x) = \frac{- 5}{3 x ^{2} - 24 x + 50}

f (x) = 3 x e^{- x}

f (x) = \frac{1 - x}{9 + x}

E (x, y) = (x + 2 y)^{2} - (x - 2 y)^{2} - 4 x y

f (x) = x^{2} + x^{2} y + y^{2} + 1

What is the extreme f(x)=x^3+12x^2-27x+8[-10] ?
The extreme f(x)=x^3+12x^2-27x+8[-10] is Maximum(-9,406),Minimum(1,-94)