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Popular >

extreme f(x)=x^4+x^2

Solution

extreme points

f (x) = x^{4} + x^{2}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = 4 x^{3} + 2 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{4} + x^{2} : 0

Minimum (0, 0)

Graph

Popular Examples

extreme f(x)x^3-27x extreme points

f (x) x^{3} - 27 x

extreme f(x)=3x^2-2x+4 extreme points

f (x) = 3 x^{2} - 2 x + 4

extreme f(x)=x^2-14x+9 extreme points

f (x) = x^{2} - 14 x + 9

extreme f(x)=380x^2-3800x^3 extreme points

f (x) = 380 x^{2} - 3800 x^{3}

extreme-x^3+2x^2+3x extreme points

- x^{3} + 2 x^{2} + 3 x

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^4+x^2 ?
The extreme f(x)=x^4+x^2 is Minimum(0,0)