What is the extreme f(x,y)=-2x-2y-x^2-y^2 ?

The extreme f(x,y)=-2x-2y-x^2-y^2 is Maximum(-1,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=-2x-2y-x^2-y^2

extreme points

f (x, y) = - 2 x - 2 y - x^{2} - y^{2}

Maximum (- 1, - 1)

Solution steps

Find the critical points:

(- 1, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(- 1, - 1) :

Maximum

Maximum (- 1, - 1)

f (x) = x y + \frac{1}{x} + \frac{1}{y}

y = 3 x^{2} - 4 x, 0 \leq x \leq 3

f (x) = x^{5} - 5 x - 10

f (x) = 4 - \frac{16}{3} x^{2}, 0 \leq x \leq \frac{1}{2}

f (x) = x^{2} - 5 x - 2

What is the extreme f(x,y)=-2x-2y-x^2-y^2 ?
The extreme f(x,y)=-2x-2y-x^2-y^2 is Maximum(-1,-1)