What is the extreme f(x)=xsqrt(x+6) ?

The extreme f(x)=xsqrt(x+6) is Maximum(-6,0),Minimum(-4,-4sqrt(2))

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extreme f(x)=xsqrt(x+6)

extreme points

f (x) = x x + 6

Maximum (- 6, 0), Minimum (- 4, - 42)

Solution steps

f^{'} (x) = \frac{3 x + 12}{2 x + 6}

Find intervals:

Decreasing

: - 6 < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 6

into

x x + 6 : 0

Maximum (- 6, 0)

Plug

x = - 4

into

x x + 6 : - 42

Minimum (- 4, - 42)

Maximum (- 6, 0), Minimum (- 4, - 42)

f (x, y) = x^{2} + y^{2} + 10 x - 4 y

f (x) = 5 x - 4 ln (3 x)

\frac{6}{x + 7}

g (x, y) = - 4 c x + 4 y x

f (x, y) = (x^{2} + y^{2})^{2} = 2 \cdot (x^{2} - y^{2})

What is the extreme f(x)=xsqrt(x+6) ?
The extreme f(x)=xsqrt(x+6) is Maximum(-6,0),Minimum(-4,-4sqrt(2))