What is the extreme f(x)=-x^3-3x^2+24x-6 ?

The extreme f(x)=-x^3-3x^2+24x-6 is Minimum(-4,-86),Maximum(2,22)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-x^3-3x^2+24x-6

extreme points

f (x) = - x^{3} - 3 x^{2} + 24 x - 6

Minimum (- 4, - 86), Maximum (2, 22)

Solution steps

f^{'} (x) = - 3 x^{2} - 6 x + 24

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = - 4

into

- x^{3} - 3 x^{2} + 24 x - 6 : - 86

Minimum (- 4, - 86)

Plug

x = 2

into

- x^{3} - 3 x^{2} + 24 x - 6 : 22

Maximum (2, 22)

Minimum (- 4, - 86), Maximum (2, 22)

f (x) = 1 - 2 x, x \geq - 1

4 x^{3} e^{- x}

f (x) = 9 sin (x) + 9 cos (x), 0 \leq x \leq 2 π

f (x) = ln (8 - ln (x))

f (x) = \frac{2 ( - 2 x ^{2} + 4 )}{4 - x ^{2}}

What is the extreme f(x)=-x^3-3x^2+24x-6 ?
The extreme f(x)=-x^3-3x^2+24x-6 is Minimum(-4,-86),Maximum(2,22)