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Popular >

extreme f(x)=3x^2+x-1

Solution

extreme points

f (x) = 3 x^{2} + x - 1

Solution

Minimum (- \frac{1}{6}, - \frac{13}{12})

Solution steps

f^{'} (x) = 6 x + 1

Find intervals:

Decreasing

: - \infty < x < - \frac{1}{6},

Increasing

: - \frac{1}{6} < x < \infty

Plug

x = - \frac{1}{6}

into

3 x^{2} + x - 1 : - \frac{13}{12}

Minimum (- \frac{1}{6}, - \frac{13}{12})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=3x^2+x-1 ?
The extreme f(x)=3x^2+x-1 is Minimum(-1/6 ,-13/12)