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Popular >

extreme f(x)= 2/(x^2-2x-3)

Solution

extreme points

f (x) = \frac{2}{x ^{2} - 2 x - 3}

Solution

Maximum (1, - \frac{1}{2})

Solution steps

f^{'} (x) = - \frac{2 ( 2 x - 2 )}{( x ^{2} - 2 x - 3 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = 1

into

\frac{2}{x ^{2} - 2 x - 3} : - \frac{1}{2}

Maximum (1, - \frac{1}{2})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)= 2/(x^2-2x-3) ?
The extreme f(x)= 2/(x^2-2x-3) is Maximum(1,-1/2)