What is the extreme f(x)=2xy+3x+4y ?

The extreme f(x)=2xy+3x+4y is Saddle(-2,-3/2)

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extreme f(x)=2xy+3x+4y

extreme points

f (x) = 2 x y + 3 x + 4 y

Saddle (- 2, - \frac{3}{2})

Solution steps

Find the critical points:

(- 2, - \frac{3}{2})

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 4

Check the sign of at each critical point

Check critical point

(- 2, - \frac{3}{2}) :

Saddle

Saddle (- 2, - \frac{3}{2})

f (x) = \frac{6}{- 5 x - 2}

f (x) = - \frac{50 x}{x ^{2} + 25}

2 x^{4} + 2 y^{4} - x y

f (x, y) = - x^{4} + 2 y^{4} + 18 x^{2} - 36 y^{2} + 2

f (x) = 7 x + \frac{1}{x}

What is the extreme f(x)=2xy+3x+4y ?
The extreme f(x)=2xy+3x+4y is Saddle(-2,-3/2)