What is the extreme f(x,y,z)=x-xy+2^2 ?

The extreme f(x,y,z)=x-xy+2^2 is Saddle(0,1)

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extreme f(x,y,z)=x-xy+2^2

extreme points

f (x, y, z) = x - x y + 2^{2}

Saddle (0, 1)

Solution steps

Find the critical points:

(0, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(0, 1) :

Saddle

Saddle (0, 1)

81 - x^{2}, - 9 \leq x \leq 9

\frac{( - 4 )}{x - 7}

f (x) = (x - 3 x^{2})^{\frac{1}{5}}, - 1 \leq x \leq 5

g (x) = x 2 - x^{2}

ln (x^{2} + 144)

What is the extreme f(x,y,z)=x-xy+2^2 ?
The extreme f(x,y,z)=x-xy+2^2 is Saddle(0,1)