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Popular >

extreme f(x)=11+7x+x^2

Solution

extreme points

f (x) = 11 + 7 x + x^{2}

Solution

Minimum (- \frac{7}{2}, - \frac{5}{4})

Solution steps

f^{'} (x) = 2 x + 7

Find intervals:

Decreasing

: - \infty < x < - \frac{7}{2},

Increasing

: - \frac{7}{2} < x < \infty

Plug

x = - \frac{7}{2}

into

11 + 7 x + x^{2} : - \frac{5}{4}

Minimum (- \frac{7}{2}, - \frac{5}{4})

Popular Examples

extreme f(x)=(3x)/(x^2+7),0<= x<= 4 extreme points

f (x) = \frac{3 x}{x ^{2} + 7}, 0 \leq x \leq 4

extreme y=x^2+2x-1 extreme points

y = x^{2} + 2 x - 1

extreme f(x)=x^4+16x^3-6 extreme points

f (x) = x^{4} + 16 x^{3} - 6

extreme f(x)=(x^2+1)/(3x+0)extreme points

f (x) = \frac{x ^{2} + 1}{3 x + 0}

extreme (2x+1)/(x-1)extreme points

\frac{2 x + 1}{x - 1}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=11+7x+x^2 ?
The extreme f(x)=11+7x+x^2 is Minimum(-7/2 ,-5/4)