What is the extreme f(x)=(2x+5)/3 ,(0,5) ?

The extreme f(x)=(2x+5)/3 ,(0,5) is None

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extreme f(x)=(2x+5)/3 ,(0,5)

extreme points

f (x) = \frac{2 x + 5}{3}, (0, 5)

None

Solution steps

Find the critical points:

None

\frac{2 x + 5}{3}

has no critical points, therefore there are no extreme points

None

f (x) = \frac{( 1 )}{( 3 ) x ^{(3)} - 400 x}

f (x, y) = x^{2} + x y + 2 x + 4 y + 1

f (x) = x^{3} + 3 x^{2} + 2 x

f (x) = 2 x^{3} - 21 x^{2} + 60 x, 1 \leq x \leq 6

What is the extreme f(x)=(2x+5)/3 ,(0,5) ?
The extreme f(x)=(2x+5)/3 ,(0,5) is None