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Popular >

extreme (x-5)/(x^2-16x+64)

Solution

extreme points

\frac{x - 5}{x ^{2} - 16 x + 64}

Solution

Minimum (2, - \frac{1}{12})

Solution steps

f^{'} (x) = - \frac{x - 2}{( x - 8 ) ^{3}}

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < 8,

Decreasing

: 8 < x < \infty

Plug

x = 2

into

\frac{x - 5}{x ^{2} - 16 x + 64} : - \frac{1}{12}

Minimum (2, - \frac{1}{12})

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Frequently Asked Questions (FAQ)

What is the extreme (x-5)/(x^2-16x+64) ?
The extreme (x-5)/(x^2-16x+64) is Minimum(2,-1/12)