What is the extreme f(x)=x^3*ln(x) ?

The extreme f(x)=x^3*ln(x) is Minimum(1/(\sqrt[3]{e)},-1/(3e))

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extreme f(x)=x^3*ln(x)

extreme points

f (x) = x^{3} \cdot ln (x)

Solution steps

f^{'} (x) = 3 x^{2} ln (x) + x^{2}

Find intervals:

Decreasing

Increasing

Plug

into

x^{3} \cdot ln (x) : - \frac{1}{3 e}

f (x) = x^{3} + 3 x^{2} + 5, - 3 \leq x \leq 2

2 (x - 1) (x^{2} + 1) (3 x^{2} - 2 x + 1)

f (x) = x (26 - 40 + 2 x) (\frac{40}{2} - x)

e^{x^{3} - 12 x}, 0 \leq x \leq 3

f (x, y) = 2 x + 3 y x^{2}

What is the extreme f(x)=x^3*ln(x) ?
The extreme f(x)=x^3*ln(x) is Minimum(1/(\sqrt[3]{e)},-1/(3e))