What is the extreme f(x)=x(10+x),-1<= x<= 3 ?

The extreme f(x)=x(10+x),-1<= x<= 3 is Minimum(-1,-9),Maximum(3,39)

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extreme f(x)=x(10+x),-1<= x<= 3

extreme points

f (x) = x (10 + x), - 1 \leq x \leq 3

Minimum (- 1, - 9), Maximum (3, 39)

Solution steps

Find the critical points:

x = - 1, x = 3

Domain of

x (10 + x), - 1 \leq x \leq 3 : - 1 \leq x \leq 3

Find intervals:

Increasing

: - 1 < x < 3

Plug the extreme point

x = - 1

into

x (10 + x) \Rightarrow y = - 9

Minimum (- 1, - 9)

Plug the extreme point

x = 3

into

x (10 + x) \Rightarrow y = 39

Maximum (3, 39)

Minimum (- 1, - 9), Maximum (3, 39)

y = x (10 - 2 x) (8 - x)

f (x) = \frac{3 x ^{2} - 16 x + 16}{( x ^{2} - 2 x ) ^{2}}

- x^{\frac{2}{3}} (x - 5)

f (x) = x + e^{- 4 x}, - 2 \leq x \leq 2

f (x, y) = x + 2 y - 2 x y - x^{2} - 3 y^{2}

What is the extreme f(x)=x(10+x),-1<= x<= 3 ?
The extreme f(x)=x(10+x),-1<= x<= 3 is Minimum(-1,-9),Maximum(3,39)