What is the extreme f(x)=x^3+3x^2-9 ?

The extreme f(x)=x^3+3x^2-9 is Maximum(-2,-5),Minimum(0,-9)

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extreme f(x)=x^3+3x^2-9

extreme points

f (x) = x^{3} + 3 x^{2} - 9

Maximum (- 2, - 5), Minimum (0, - 9)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

x^{3} + 3 x^{2} - 9 : - 5

Maximum (- 2, - 5)

Plug

x = 0

into

x^{3} + 3 x^{2} - 9 : - 9

Minimum (0, - 9)

Maximum (- 2, - 5), Minimum (0, - 9)

- x^{3} + 2 x^{2}

f (x) = x ln (x^{2})

f (x) = \frac{x ^{2} - 11 x + 67}{x - 9}

f (x) = - x^{3} + 3 x + 7

f (x) = x ln (9 x)

What is the extreme f(x)=x^3+3x^2-9 ?
The extreme f(x)=x^3+3x^2-9 is Maximum(-2,-5),Minimum(0,-9)