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Popular >

extreme f(x)=4+3x+x^2

Solution

extreme points

f (x) = 4 + 3 x + x^{2}

Solution

Minimum (- \frac{3}{2}, \frac{7}{4})

Solution steps

f^{'} (x) = 2 x + 3

Find intervals:

Decreasing

: - \infty < x < - \frac{3}{2},

Increasing

: - \frac{3}{2} < x < \infty

Plug

x = - \frac{3}{2}

into

4 + 3 x + x^{2} : \frac{7}{4}

Minimum (- \frac{3}{2}, \frac{7}{4})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=4+3x+x^2 ?
The extreme f(x)=4+3x+x^2 is Minimum(-3/2 , 7/4)