What is the extreme f(x)=-(56)/(81(x+1)^{10/3)} ?

The extreme f(x)=-(56)/(81(x+1)^{10/3)} is None

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extreme f(x)=-(56)/(81(x+1)^{10/3)}

extreme points

f (x) = - \frac{56}{81 ( x + 1 ) ^{\frac{10}{3}}}

None

Solution steps

f^{'} (x) = \frac{560}{243 ( x + 1 ) ^{\frac{13}{3}}}

Find intervals:

None

None

f (x) = \frac{- 1}{x - 2}

f (x) = \frac{- 1}{x - 7}

y = 2 x^{3} - 6 x + 3

f (x) = 1 - x^{\frac{2}{3}}

f (x) = 12 x + y - 14

What is the extreme f(x)=-(56)/(81(x+1)^{10/3)} ?
The extreme f(x)=-(56)/(81(x+1)^{10/3)} is None