What is the extreme f(x)=-2x^3+36x^2-120x+11 ?

The extreme f(x)=-2x^3+36x^2-120x+11 is Minimum(2,-101),Maximum(10,411)

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extreme f(x)=-2x^3+36x^2-120x+11

extreme points

f (x) = - 2 x^{3} + 36 x^{2} - 120 x + 11

Minimum (2, - 101), Maximum (10, 411)

Solution steps

f^{'} (x) = - 6 x^{2} + 72 x - 120

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < 10,

Decreasing

: 10 < x < \infty

Plug

x = 2

into

- 2 x^{3} + 36 x^{2} - 120 x + 11 : - 101

Minimum (2, - 101)

Plug

x = 10

into

- 2 x^{3} + 36 x^{2} - 120 x + 11 : 411

Maximum (10, 411)

Minimum (2, - 101), Maximum (10, 411)

f (x) = 8 + 5 x - 5 x^{2}

f (x) = x (23 - 48 + 2 x) (\frac{48}{2} - x)

f (x) = \frac{x + 5}{x + 3}

f (x, y) = 4 x^{2} - 12 x + y^{2} + 2 y - 10

p (x) = 12 x^{4} + 21 x^{3} + a x^{2} - 21 x - 9

What is the extreme f(x)=-2x^3+36x^2-120x+11 ?
The extreme f(x)=-2x^3+36x^2-120x+11 is Minimum(2,-101),Maximum(10,411)