What is the extreme f(x)=(12-2x)(12-2x)x ?

The extreme f(x)=(12-2x)(12-2x)x is Maximum(2,128),Minimum(6,0)

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extreme f(x)=(12-2x)(12-2x)x

extreme points

f (x) = (12 - 2 x) (12 - 2 x) x

Maximum (2, 128), Minimum (6, 0)

Solution steps

f^{'} (x) = 12 (x - 6) (x - 2)

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 2

into

(12 - 2 x) (12 - 2 x) x : 128

Maximum (2, 128)

Plug

x = 6

into

(12 - 2 x) (12 - 2 x) x : 0

Minimum (6, 0)

Maximum (2, 128), Minimum (6, 0)

f (x) = \frac{5 x}{x ^{2} + 25}

f (x) = - x^{3} + 12 x - 18

y = (x - 1)^{5}

f (x) = - x^{3} + 12 x - 25

f (x) = - x^{3} + 12 x - 23

What is the extreme f(x)=(12-2x)(12-2x)x ?
The extreme f(x)=(12-2x)(12-2x)x is Maximum(2,128),Minimum(6,0)