What is the extreme h(x)=2x^3-24x ?

The extreme h(x)=2x^3-24x is Maximum(-2,32),Minimum(2,-32)

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extreme h(x)=2x^3-24x

extreme points

h (x) = 2 x^{3} - 24 x

Maximum (- 2, 32), Minimum (2, - 32)

Solution steps

f^{'} (x) = 6 x^{2} - 24

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

2 x^{3} - 24 x : 32

Maximum (- 2, 32)

Plug

x = 2

into

2 x^{3} - 24 x : - 32

Minimum (2, - 32)

Maximum (- 2, 32), Minimum (2, - 32)

y = x x^{2} + 1

f (x) = 4 x^{2} + y^{2}

f (x) = ln (4 x)

x^{3} - y^{3} - 2 x y + 6

f (x) = x^{\frac{1}{7}} (x - 8)

What is the extreme h(x)=2x^3-24x ?
The extreme h(x)=2x^3-24x is Maximum(-2,32),Minimum(2,-32)