en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^5+243

Solution

extreme points

f (x) = x^{5} + 243

Solution

Saddle (0, 243)

Solution steps

f^{'} (x) = 5 x^{4}

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{5} + 243 : 243

Saddle (0, 243)

Graph

Popular Examples

extreme f(x)=6-(x^3)/3+15x-x^2 extreme points

f (x) = 6 - \frac{x ^{3}}{3} + 15 x - x^{2}

extreme f(x)=3x^2-12x+7,0<= x<= 4 extreme points

f (x) = 3 x^{2} - 12 x + 7, 0 \leq x \leq 4

extreme (x-1)^3-3x extreme points

(x - 1)^{3} - 3 x

extreme f(x,y)=x^2+xy+y^2-6x extreme points

f (x, y) = x^{2} + x y + y^{2} - 6 x

extreme f(x)=40x^2+(600)/x extreme points

f (x) = 40 x^{2} + \frac{600}{x}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^5+243 ?
The extreme f(x)=x^5+243 is Saddle(0,243)