What is the extreme x^2+y^2-2x-2y+3 ?

The extreme x^2+y^2-2x-2y+3 is Minimum(1,1)

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extreme x^2+y^2-2x-2y+3

extreme points

x^{2} + y^{2} - 2 x - 2 y + 3

Minimum (1, 1)

Solution steps

Find the critical points:

(1, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(1, 1) :

Minimum

Minimum (1, 1)

f (t) = 5 u t (t - 2)

f (x) = 3 x^{2} - 3 y^{2} + 6

x^{2} + y^{2} + 4 x - 2 y + 6

f (x) = 8 y^{3} - 12 x y + x^{3}

f (x) = 5 x 16 - x^{2}

What is the extreme x^2+y^2-2x-2y+3 ?
The extreme x^2+y^2-2x-2y+3 is Minimum(1,1)